By now it’s become fairly obvious that Google’s new social network, Google+, is here to stay (unlike some of the company’s past efforts at being social): depending on which estimates you believe, Google+ may have as many as 50 million registered users, which is not bad for a three-month old product. And the company has made it clear that it wants to use Google+ as a kind of identity platform for other things — hence the importance of its controversial “real name” policy. But it wasn’t obvious just how much was riding on the new network until recently, thanks in part to some comments made by vice-president of product Brad Horowitz, who said that in the future, Google+ and Google will effectively become inseparable.
via It’s official: Google+ will be connected to everything — Tech News and Analysis.
Pingback: buying viagra online legally()
Pingback: buy cialis online()
Pingback: buy generic cialis online()
Pingback: casino games win real money()
Pingback: buy cialis()
Pingback: viagra cost()
Pingback: loans online()
Pingback: generic for lumigan eye drops()
Pingback: order viagra without prescription()
Pingback: slot machine games()
Pingback: viagra dosage()
Pingback: best casino online()
Pingback: cialis ed()
Pingback: vardenafil 20 mg()
Pingback: levitra for sale()
Pingback: Buy cialis()
Pingback: canadian pharmacy()
Pingback: can i buy chloroquine over the counter()
Pingback: top erection pills()
Pingback: cheap ed pills()
Pingback: viagra for sale()
Pingback: how does viagra work()
Pingback: tylenol 500 mg generic()
Pingback: cialis savings card()
Pingback: buy careprost()
Pingback: how long does viagra last()
Pingback: discount cialis()
Pingback: cialis prices()
Pingback: naltrexone price in india()
Pingback: cialis from canada()
Pingback: albuterol inhaler()
Pingback: is there a generic cialis()
Pingback: generic cialis from usa pharmacy()
Pingback: Generic viagra in canada()
Pingback: Order viagra()
Pingback: generic cialis india()
Pingback: price of cialis()
Pingback: prices of cialis()
Pingback: Free viagra()